(x^1/2y^-3/5/x^0y^-2/5)^-5

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Solution for (x^1/2y^-3/5/x^0y^-2/5)^-5 equation:


D( x )

x^0 = 0

x = 0

((((((x^1)/2)*y^-3)/5)/(x^0))*y^-2)/5 = 0

x^0 = 0

x^0 = 0

1 = 0

x^0 = 0

1 = 0

x belongs to the empty set

x = 0

x = 0

((((((x^1)/2)*y^-3)/5)/(x^0))*y^-2)/5 = 0

((((((x^1)/2)*y^-3)/5)/(x^0))*y^-2)/5 = 0

((((x/2)*y^-3)/5)*y^-2)/5 = 0

1/50*x*y^-5 = 0 // : 1/50*y^-5

x = 0

x in (-oo:0) U (0:+oo)

(((((((x^1)/2)*y^-3)/5)/(x^0))*y^-2)/5)^-5 = 0

(((((x/2)*y^-3)/5)*y^-2)/5)^-5 = 0

312500000*x^-5*y^25 = 0 // : 312500000*y^25

x^-5 = 0

x należy do O

x belongs to the empty set

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